Caso # | Resultado | Tiempo | Memoria |
---|---|---|---|
#1 |
Correcto
|
0.019 s | 3 KBi |
#2 |
Correcto
|
0.022 s | 3 KBi |
#3 |
Correcto
|
0.033 s | 3 KBi |
#4 |
Correcto
|
0.019 s | 3 KBi |
#5 |
Correcto
|
0.026 s | 3 KBi |
#6 |
Correcto
|
0.023 s | 3 KBi |
#7 |
Correcto
|
0.023 s | 3 KBi |
#8 |
Correcto
|
0.017 s | 3 KBi |
#9 |
Correcto
|
0.027 s | 3 KBi |
#10 |
Correcto
|
0.026 s | 3 KBi |
#11 |
Correcto
|
0.02 s | 3 KBi |
#12 |
Correcto
|
0.022 s | 3 KBi |
#13 |
Correcto
|
0.025 s | 3 KBi |
#14 |
Correcto
|
0.021 s | 3 KBi |
#15 |
Correcto
|
0.02 s | 3 KBi |
#16 |
Correcto
|
0.024 s | 3 KBi |
#17 |
Correcto
|
0.137 s | 12 KBi |
#18 |
Correcto
|
0.175 s | 12 KBi |
#19 |
Correcto
|
0.133 s | 12 KBi |
#20 |
Correcto
|
0.144 s | 12 KBi |
#21 |
Correcto
|
0.131 s | 11 KBi |
#22 |
Correcto
|
0.143 s | 11 KBi |
#23 |
Correcto
|
0.139 s | 11 KBi |
#24 |
Correcto
|
0.145 s | 11 KBi |
# Dynamic programming n = int(input()) a = [int(i) for i in input().split()] dp = [0] * len(a) dp[0] = a[0] best = dp[0] for i in range(1, n): dp[i] = max(a[i], dp[i -1] + a[i]) best = max(best, dp[i]) print(best)