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Envío 4022

Problema 0xf2 - Partir un arreglo grande en 2

  • Autor: vander idme
  • Fecha: 2021-04-29 04:25:38 UTC (Hace casi 3 años)
Caso # Resultado Tiempo Memoria
#1
Correcto
0.019 s 3 KBi
#2
Correcto
0.02 s 3 KBi
#3
Correcto
0.026 s 3 KBi
#4
Incorrecto
0.02 s 3 KBi
#5
Incorrecto
0.02 s 3 KBi
#6
Incorrecto
0.016 s 3 KBi
#7
Incorrecto
0.02 s 3 KBi
#8
Incorrecto
0.022 s 3 KBi
#9
Incorrecto
0.029 s 3 KBi
#10
Incorrecto
0.02 s 3 KBi
#11
Incorrecto
0.016 s 3 KBi
#12
Incorrecto
0.022 s 3 KBi
#13
Incorrecto
0.023 s 3 KBi
#14
Incorrecto
0.691 s 48 KBi
#15
Incorrecto
0.583 s 42 KBi
#16
Incorrecto
0.555 s 29 KBi
#17
Incorrecto
0.741 s 30 KBi
#18
Incorrecto
0.724 s 30 KBi
#19
Incorrecto
0.585 s 29 KBi
#20
Incorrecto
0.782 s 66 KBi
Puntos totales: 15 / 100

Código

n = input()
n = int(n)
array_input = input()

array = [int(x) for x in array_input.split()]
left = array
right = array[::-1]

b_left = []
b_right = []

j = n - 1
for i in range(0, n):
    if i == 0:
        left[i] = array[i]
    else:
        left[i] = left[i] + left[i-1]
        right[i] = right[i] + right[i-1]

    if left[i] > 0:
        b_left.append(i)
    if right[i] < 0:
        b_right.append(j)
    j -= 1

b_right = b_right[::-1]

if b_right and b_left:
    c = 0
    while c < len(b_right):
        if b_right[c] in b_left:
            print(b_right[c])
            exit()
        else:
            print('Impossible')
            exit()
        c += 1
else:
    print('Impossible')

print(b_left)
print(b_right)