Caso # | Resultado | Tiempo | Memoria |
---|---|---|---|
#1 |
Correcto
|
0.005 s | 2 KBi |
#2 |
Correcto
|
0.005 s | 1 KBi |
#3 |
Correcto
|
0.007 s | 1 KBi |
#4 |
Correcto
|
0.006 s | 2 KBi |
#5 |
Correcto
|
0.007 s | 2 KBi |
#6 |
Correcto
|
0.007 s | 1 KBi |
#7 |
Correcto
|
0.005 s | 2 KBi |
#8 |
Correcto
|
0.006 s | 1 KBi |
#9 |
Correcto
|
0.005 s | 2 KBi |
#10 |
Correcto
|
0.006 s | 1 KBi |
#11 |
Correcto
|
0.005 s | 2 KBi |
#12 |
Correcto
|
0.005 s | 2 KBi |
#13 |
Correcto
|
0.006 s | 1 KBi |
#14 |
Correcto
|
0.006 s | 2 KBi |
#15 |
Correcto
|
0.007 s | 1 KBi |
#16 |
Correcto
|
0.005 s | 1 KBi |
#17 |
Incorrecto
|
0.021 s | 2 KBi |
#18 |
Incorrecto
|
0.018 s | 1 KBi |
#19 |
Incorrecto
|
0.018 s | 1 KBi |
#20 |
Incorrecto
|
0.024 s | 1 KBi |
#21 |
Incorrecto
|
0.013 s | 1 KBi |
#22 |
Incorrecto
|
0.028 s | 1 KBi |
#23 |
Correcto
|
0.014 s | 2 KBi |
#24 |
Correcto
|
0.02 s | 2 KBi |
#include <iostream> #include <cstring> #include <cstdio> #include <cmath> #include <queue> #include <set> #include <map> #include <vector> #include <stack> #include <algorithm> #define forn(a, n) for(int a = 0; a<(int) (n); ++a) #define rforn(a, n) for(int a = (n)-1; a>=0; --a) using namespace std; const int N = 6e5+20; int main() { ios_base::sync_with_stdio(false); cin.tie(NULL); int n; cin>>n; vector<int> nums (n+1); //vector<int> sums (n+1); para otra solución for(int i = 0; i < n; i++) { cin>>nums[i]; } int minimo = 0; int suma = 0; int res = nums[0]; for(int i = 0; i < n; i++) { //Mejia's algorithm suma += nums[i]; res = max(res, suma-minimo); minimo = min(minimo, suma); } cout<<res<<endl; }