Caso # | Resultado | Tiempo | Memoria |
---|---|---|---|
#1 |
Correcto
|
0.007 s | 23 KBi |
#2 |
Correcto
|
0.004 s | 1 KBi |
#3 |
Correcto
|
0.005 s | 1 KBi |
#4 |
Correcto
|
0.006 s | 3 KBi |
#5 |
Correcto
|
0.006 s | 2 KBi |
#6 |
Correcto
|
0.005 s | 2 KBi |
#7 |
Correcto
|
0.006 s | 1 KBi |
#8 |
Correcto
|
0.007 s | 5 KBi |
#9 |
Correcto
|
0.006 s | 2 KBi |
#10 |
Correcto
|
0.005 s | 2 KBi |
#11 |
Correcto
|
0.004 s | 2 KBi |
#12 |
Correcto
|
0.006 s | 17 KBi |
#13 |
Correcto
|
0.006 s | 26 KBi |
#14 |
Correcto
|
0.006 s | 5 KBi |
#15 |
Correcto
|
0.006 s | 1 KBi |
#16 |
Correcto
|
0.006 s | 2 KBi |
#17 |
Correcto
|
0.062 s | 10 KBi |
#18 |
Correcto
|
0.059 s | 2 KBi |
#19 |
Correcto
|
0.061 s | 2 KBi |
#20 |
Correcto
|
0.059 s | 2 KBi |
#21 |
Correcto
|
0.049 s | 2 KBi |
#22 |
Correcto
|
0.049 s | 2 KBi |
#23 |
Correcto
|
0.038 s | 16 KBi |
#24 |
Correcto
|
0.04 s | 2 KBi |
#include <vector> #include <iostream> #include <limits> using namespace std; int main() { int n; cin >> n; vector<long long> a(n); for (int i = 0; i < n; i++) { cin >> a[i]; } long long best = a[0]; long long sum = 0; long long smallest = 0; for (int j = 0; j < n; j++) { sum += a[j]; // Aquí, sum es S[j] // Aquí, smallest es min(0, S[0], S[1], S[2], ..., S[j-1]) best = max(best, sum - smallest); // Aquí, actualizamos smallest para que siga estando al día // en la próxima iteración. smallest = min(smallest, sum); // Aquí, smallest es min(0, S[0], S[1], S[2], ..., S[j-1], S[j]) } cout << best << endl; return 0; }