Caso # | Resultado | Tiempo | Memoria |
---|---|---|---|
#1 |
Correcto
|
0.005 s | 6 KBi |
#2 |
Correcto
|
0.005 s | 1 KBi |
#3 |
Correcto
|
0.006 s | 1 KBi |
#4 |
Correcto
|
0.005 s | 1 KBi |
#5 |
Correcto
|
0.005 s | 1 KBi |
#6 |
Correcto
|
0.005 s | 16 KBi |
#7 |
Correcto
|
0.005 s | 1 KBi |
#8 |
Correcto
|
0.005 s | 1 KBi |
#9 |
Correcto
|
0.005 s | 1 KBi |
#10 |
Correcto
|
0.005 s | 7 KBi |
#11 |
Correcto
|
0.006 s | 1 KBi |
#12 |
Correcto
|
0.005 s | 4 KBi |
#13 |
Correcto
|
0.005 s | 1 KBi |
#14 |
Correcto
|
0.004 s | 2 KBi |
#15 |
Correcto
|
0.005 s | 1 KBi |
#16 |
Correcto
|
0.006 s | 2 KBi |
#17 |
Correcto
|
0.006 s | 1 KBi |
#18 |
Correcto
|
0.006 s | 1 KBi |
#19 |
Correcto
|
0.006 s | 6 KBi |
#20 |
Correcto
|
0.006 s | 1 KBi |
#include <iostream> using namespace std; #define endl '\n' #define ll long long const int maxi = 110; int a[maxi][maxi]; int main(){ ios::sync_with_stdio(0); cin.tie(0); int n; cin>>n; for(int i=0;i<n;i++){ for(int j=0;j<n; j++){ cin>>a[i][j]; } } int sum1=0,sum2=0,sumd1=0,sumd2=0; for(int i=0;i<n;i++){ for(int j=0;j<n; j++){ if(i==j){ sumd1+=a[i][j]; } sum1+=a[i][j]; } sum2+=a[i][0]; sumd2+=a[i][n-1-i]; } if(sumd1==sumd2&&(sum1/n)==sum2){ cout<<"Yes"<<endl; }else{ cout<<"No"<<endl; } }