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Envío 6713

Problema 0xf2 - Partir un arreglo grande en 2

  • Autor: danidiaztech
  • Fecha: 2022-10-30 04:24:02 UTC (Hace alrededor de 1 mes)
Caso # Resultado Tiempo Memoria
#1
Correcto
0.005 s 1 KBi
#2
Correcto
0.004 s 1 KBi
#3
Correcto
0.004 s 1 KBi
#4
Correcto
0.004 s 1 KBi
#5
Correcto
0.006 s 1 KBi
#6
Correcto
0.004 s 1 KBi
#7
Correcto
0.004 s 1 KBi
#8
Correcto
0.005 s 1 KBi
#9
Correcto
0.004 s 1 KBi
#10
Correcto
0.004 s 1 KBi
#11
Correcto
0.004 s 1 KBi
#12
Correcto
0.005 s 1 KBi
#13
Correcto
0.005 s 1 KBi
#14
Correcto
0.033 s 5 KBi
#15
Correcto
0.036 s 5 KBi
#16
Correcto
0.029 s 5 KBi
#17
Correcto
0.028 s 5 KBi
#18
Correcto
0.027 s 5 KBi
#19
Correcto
0.024 s 5 KBi
#20
Correcto
0.036 s 5 KBi
Puntos totales: 100 / 100

Código

// Made by Daniel Diaz (@Danidiaztech)
#include <bits/stdc++.h>
using namespace std;

#define endl '\n'
#define fastInp cin.tie(0); cout.tie(0); ios_base::sync_with_stdio(0);
#define forn(i, n) for (int i = 0; i < n; i++) // for in range in python
#define FOR(i, a, b) for (int i = a; i < b; i++) // for in range in python
#define int long long int
#define double long double
#define pb push_back
#define ff first
#define ss second
#define mk make_pair

typedef pair<int, int> pii;

const int MAX = 1e6;
const int MIN = -MAX;
const int INF = LLONG_MAX;
const int MINF = LLONG_MIN;
const int MOD = 1e9 + 7;

// int arr[MAX];
void solve(){
  int n;
  cin >> n;
  int a[n];
  int s= 0;
  forn(i,n){
    cin >> a[i];
    s+=a[i];
  }

  int right = s, left = 0;
  for (int i = 0; i < n; i++){
    left += a[i];
    right -= a[i];
    if (left > 0 && right < 0){
      cout << i + 1 << endl;
      return;
    }
  }

  cout << "Impossible" << endl;
}

int32_t main() {
  fastInp;
  #if LOCAL
    freopen("input.txt", "r", stdin);
    freopen("output.txt", "w", stdout);
  #endif

  int tc = 1;
  // cin >> tc;

  for (int t = 1; t <= tc; t++){
    // cout << "Case #" << t << ": ";
    solve();
  }
  return 0;
}