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Envío 6090

Problema 0xde - Ordenar un arreglo grande

Caso # Resultado Tiempo Memoria
#1
Correcto
0.002 s 0 KBi
#2
Correcto
0.007 s 2 KBi
#3
Correcto
0.001 s 0 KBi
#4
Correcto
0.002 s 0 KBi
#5
Correcto
0.002 s 0 KBi
#6
Correcto
0.002 s 0 KBi
#7
Correcto
0.015 s 1 KBi
#8
Correcto
0.019 s 1 KBi
#9
Correcto
0.014 s 1 KBi
#10
Correcto
0.029 s 3 KBi
#11
Correcto
0.023 s 2 KBi
#12
Correcto
0.031 s 4 KBi
#13
Correcto
0.015 s 2 KBi
#14
Correcto
0.016 s 2 KBi
#15
Correcto
0.016 s 2 KBi
#16
Correcto
0.025 s 2 KBi
#17
Correcto
0.059 s 6 KBi
#18
Correcto
0.024 s 3 KBi
#19
Correcto
0.03 s 3 KBi
#20
Correcto
0.015 s 1 KBi
#21
Correcto
0.016 s 2 KBi
#22
Correcto
0.022 s 3 KBi
#23
Correcto
0.023 s 3 KBi
#24
Correcto
0.017 s 2 KBi
#25
Correcto
0.026 s 3 KBi
#26
Correcto
0.022 s 2 KBi
#27
Correcto
0.028 s 3 KBi
Puntos totales: 100 / 100

Código

#include <bits/stdc++.h>
using namespace std;

void merge(int *arr, int l, int m, int r){
    int i, j, k;
    int n1 = m - l + 1;
    int n2 = r - m;
    int L[n1], R[n2];

    for (i = 0; i < n1; i++)
        L[i] = arr[l + i];
    for (j = 0; j < n2; j++)
        R[j] = arr[m + 1 + j];
  
    i = 0; // Initial index of first subarray
    j = 0; // Initial index of second subarray
    k = l; // Initial index of merged subarray
    while (i < n1 && j < n2) {
        if (L[i] <= R[j]) {
            arr[k] = L[i];
            i++;
        }
        else {
            arr[k] = R[j];
            j++;
        }
        k++;
    }
  
    while (i < n1) {
        arr[k] = L[i];
        i++;
        k++;
    }
  
    while (j < n2) {
        arr[k] = R[j];
        j++;
        k++;
    }
}

void mergeSort(int *arr, int l, int r){
    if(l>=r || l<0) return;
    int m = l + (r-l)/2;
    mergeSort(arr, l, m);
    mergeSort(arr, m+1, r);
    merge(arr, l, m, r);
}

int main() {
    ios_base::sync_with_stdio(false);
    cin.tie(NULL); 
    // your code goes here
    int N, i;
    cin >> N;
    int arr[N];
    for(i=0; i<N; i++)
        cin >> arr[i];
    mergeSort(arr, 0, N-1);
    for(i=0; i<N; i++)
        cout << arr[i] << " ";
    cout << "\n";
	return 0;
}