Envío 4375
Problema 0x31 - Sumarle un dígito a número muy grande
- Autor: Andres Ariza
- Fecha: 2021-06-14 18:26:34 UTC (Hace más de 3 años)
| Caso # | Resultado | Tiempo | Memoria |
|---|---|---|---|
| #1 |
Incorrecto
|
0.027 s | 3 KBi |
| #2 |
Incorrecto
|
0.022 s | 3 KBi |
| #3 |
Incorrecto
|
0.022 s | 3 KBi |
| #4 |
Incorrecto
|
0.022 s | 3 KBi |
| #5 |
Incorrecto
|
0.029 s | 3 KBi |
| #6 |
Incorrecto
|
0.02 s | 3 KBi |
| #7 |
Incorrecto
|
0.02 s | 3 KBi |
| #8 |
Incorrecto
|
0.028 s | 3 KBi |
| #9 |
Incorrecto
|
0.024 s | 3 KBi |
| #10 |
Incorrecto
|
0.027 s | 3 KBi |
| #11 |
Incorrecto
|
0.02 s | 3 KBi |
| #12 |
Incorrecto
|
0.023 s | 3 KBi |
| #13 |
Incorrecto
|
0.021 s | 3 KBi |
| #14 |
Incorrecto
|
0.024 s | 3 KBi |
| #15 |
Incorrecto
|
0.028 s | 4 KBi |
| #16 |
Incorrecto
|
0.021 s | 3 KBi |
| #17 |
Incorrecto
|
0.028 s | 3 KBi |
| #18 |
Incorrecto
|
0.032 s | 3 KBi |
| #19 |
Incorrecto
|
0.03 s | 3 KBi |
| #20 |
Incorrecto
|
0.02 s | 3 KBi |
| #21 |
Incorrecto
|
0.02 s | 3 KBi |
| #22 |
Incorrecto
|
0.025 s | 5 KBi |
| #23 |
Incorrecto
|
0.024 s | 3 KBi |
| #24 |
Incorrecto
|
0.024 s | 3 KBi |
| #25 |
Incorrecto
|
0.02 s | 3 KBi |
| #26 |
Incorrecto
|
0.02 s | 3 KBi |
| #27 |
Incorrecto
|
0.021 s | 3 KBi |
| #28 |
Incorrecto
|
0.037 s | 6 KBi |
| #29 |
Incorrecto
|
0.021 s | 3 KBi |
| #30 |
Incorrecto
|
0.033 s | 3 KBi |
| #31 |
Incorrecto
|
0.032 s | 3 KBi |
| #32 |
Incorrecto
|
0.019 s | 3 KBi |
| #33 |
Incorrecto
|
0.021 s | 3 KBi |
| #34 |
Incorrecto
|
0.023 s | 3 KBi |
| #35 |
Incorrecto
|
0.026 s | 3 KBi |
| #36 |
Incorrecto
|
0.025 s | 3 KBi |
| #37 |
Incorrecto
|
0.021 s | 3 KBi |
| #38 |
Incorrecto
|
0.022 s | 3 KBi |
| #39 |
Incorrecto
|
0.021 s | 3 KBi |
| #40 |
Incorrecto
|
0.021 s | 3 KBi |
| #41 |
Incorrecto
|
0.021 s | 3 KBi |
| #42 |
Incorrecto
|
0.02 s | 3 KBi |
Puntos totales: 0 / 100
Código
def sum_one(string: str, add: int) -> str:
number = []
i = 0
while add and i < len(string):
c, r = divmod(int(string[-i-1]) + add, 10)
number.append(str(r))
add = c
i += 1
if add:
number.append(str(add))
return "".join(list(string)[:-i] + list(reversed(number)))