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Envío 2497

Problema 0x62 - Contar elementos mayores a X en un arreglo pequeño

Caso # Resultado Tiempo Memoria
#1
Correcto
0.004 s 1 KBi
#2
Correcto
0.007 s 1 KBi
#3
Correcto
0.006 s 9 KBi
#4
Correcto
0.006 s 1 KBi
#5
Correcto
0.006 s 42 KBi
#6
Correcto
0.007 s 2 KBi
#7
Correcto
0.006 s 27 KBi
#8
Correcto
0.009 s 1 KBi
#9
Correcto
0.009 s 1 KBi
#10
Correcto
0.009 s 2 KBi
Puntos totales: 100 / 100

Código

#include<iostream>
#include<algorithm>
#include<vector>

using namespace std;

int bSearch(vector<int>& vals, int target){
    int l = 0;
    int r = vals.size()-1;
    int res = -1;
    while(l<=r){
        int m = (l+r)/2;
        if(vals[m]<target){
            l = m+1;
        }
        else if(vals[m]==target){
            res = m;
            l = m+1;
        }
        else{
            r = m-1;
            res = m;
        }
    }
    return res;
}

int main(){
    int n, c;
    cin>>n;
    vector<int>vals(n);
    for(auto &val: vals){
        cin>>val;
    }
    sort(vals.begin(),vals.end());
    cin>>c;
    for(int i=0;i<c;i++){
        int target;
        cin>>target;
        int indexElement = bSearch(vals,target);
        if(indexElement!=-1){
            if(vals[indexElement]!=target){
                cout<<vals.size()-indexElement<<endl;
            }
            else{
                cout<<vals.size()-1-indexElement<<endl;
            }
        }
        else{
            if(target>vals[vals.size()-1]){
                cout<<0<<endl;
            }
            else{
                cout<<vals.size()<<endl;
            }
        }
    }
    return 0;
}