Caso # | Resultado | Tiempo | Memoria |
---|---|---|---|
#1 |
Correcto
|
0.024 s | 3 KBi |
#2 |
Correcto
|
0.022 s | 3 KBi |
#3 |
Correcto
|
0.023 s | 3 KBi |
#4 |
Correcto
|
0.025 s | 5 KBi |
#5 |
Correcto
|
0.026 s | 3 KBi |
#6 |
Correcto
|
0.027 s | 3 KBi |
#7 |
Correcto
|
0.028 s | 3 KBi |
#8 |
Correcto
|
0.046 s | 6 KBi |
#9 |
Correcto
|
0.025 s | 3 KBi |
#10 |
Correcto
|
0.044 s | 4 KBi |
#11 |
Correcto
|
0.028 s | 3 KBi |
#12 |
Correcto
|
0.025 s | 3 KBi |
def ordenado(a): """ Determina si un arreglo esta ordenado de menor a mayor """ if len(a) == 1: return "Ordenado" for i in range(1, len(a)): if a[i] < a[i - 1]: return "Desordenado" return "Ordenado" n = int(input()) a = [int(x) for x in input().split()] print(ordenado(a))