Caso # | Resultado | Tiempo | Memoria |
---|---|---|---|
#1 |
Correcto
|
0.009 s | 4 KBi |
#2 |
Correcto
|
0.005 s | 8 KBi |
#3 |
Correcto
|
0.005 s | 1 KBi |
#4 |
Correcto
|
0.007 s | 4 KBi |
#5 |
Correcto
|
0.005 s | 1 KBi |
#6 |
Correcto
|
0.005 s | 2 KBi |
#7 |
Correcto
|
0.006 s | 2 KBi |
#8 |
Correcto
|
0.005 s | 2 KBi |
#9 |
Correcto
|
0.005 s | 3 KBi |
#10 |
Correcto
|
0.023 s | 2 KBi |
#11 |
Correcto
|
0.11 s | 2 KBi |
#12 |
Correcto
|
0.025 s | 2 KBi |
#13 |
Correcto
|
0.114 s | 2 KBi |
#14 |
Correcto
|
0.023 s | 2 KBi |
#15 |
Correcto
|
0.025 s | 9 KBi |
#16 |
Correcto
|
0.071 s | 5 KBi |
#17 |
Correcto
|
0.027 s | 2 KBi |
#18 |
Correcto
|
0.083 s | 2 KBi |
#19 |
Correcto
|
0.034 s | 10 KBi |
#20 |
Correcto
|
0.056 s | 3 KBi |
#21 |
Correcto
|
0.059 s | 2 KBi |
#22 |
Correcto
|
0.064 s | 6 KBi |
#23 |
Correcto
|
0.035 s | 2 KBi |
#24 |
Correcto
|
0.03 s | 2 KBi |
#include<bits/stdc++.h> using namespace std; int main(){ string see; cin >> see; int k; cin >> k; map<char,int> counter; int ans = 0; for(int i = 0, j = 0; j < see.size();++j){ ++counter[see[j]]; while((int)counter.size() > k){ --counter[see[i]]; if(counter[see[i]] == 0) counter.erase(see[i]); ++i; } ans = max(ans,j-i+1); } printf("%d\n",ans); return 0; }