Envío 2025
Problema 0x5c - Decir si hay una letra repetida
- Autor: d4vsanchez
- Fecha: 2020-11-19 02:38:37 UTC (Hace más de 3 años)
| Caso # | Resultado | Tiempo | Memoria |
|---|---|---|---|
| #1 |
Incorrecto
|
0.023 s | 3 KBi |
| #2 |
Incorrecto
|
0.023 s | 3 KBi |
| #3 |
Incorrecto
|
0.024 s | 3 KBi |
| #4 |
Incorrecto
|
0.032 s | 3 KBi |
| #5 |
Incorrecto
|
0.02 s | 3 KBi |
| #6 |
Incorrecto
|
0.026 s | 3 KBi |
| #7 |
Incorrecto
|
0.028 s | 3 KBi |
| #8 |
Incorrecto
|
0.027 s | 3 KBi |
| #9 |
Incorrecto
|
0.023 s | 3 KBi |
| #10 |
Incorrecto
|
0.025 s | 3 KBi |
| #11 |
Incorrecto
|
0.019 s | 3 KBi |
| #12 |
Incorrecto
|
0.021 s | 3 KBi |
Puntos totales: 0 / 100
Código
def has_repeated_letter(word):
alphabet = [0] * 26
for letter in word:
letter_number = ord(letter) - 97
if alphabet[letter_number] > 0:
return False
alphabet[letter_number] += 1
return True
word = input()
if has_repeated_letter(word):
print("yes")
else:
print("no")