Envío 2022
Problema 0x5c - Decir si hay una letra repetida
- Autor: abatesins
- Fecha: 2020-11-17 14:35:59 UTC (Hace alrededor de 4 años)
| Caso # | Resultado | Tiempo | Memoria |
|---|---|---|---|
| #1 |
Correcto
|
0.025 s | 3 KBi |
| #2 |
Correcto
|
0.026 s | 3 KBi |
| #3 |
Correcto
|
0.025 s | 3 KBi |
| #4 |
Correcto
|
0.022 s | 3 KBi |
| #5 |
Correcto
|
0.022 s | 3 KBi |
| #6 |
Correcto
|
0.023 s | 3 KBi |
| #7 |
Correcto
|
0.029 s | 4 KBi |
| #8 |
Correcto
|
0.023 s | 3 KBi |
| #9 |
Correcto
|
0.024 s | 3 KBi |
| #10 |
Correcto
|
0.027 s | 5 KBi |
| #11 |
Correcto
|
0.025 s | 3 KBi |
| #12 |
Correcto
|
0.025 s | 3 KBi |
Puntos totales: 100 / 100
Código
word = input()
HT_LEN = 26 # minimal perfect hashing with ord()
ht = [False] * HT_LEN
repeated = 'yes'
for char in word:
idx = ord(char) - 97 # ord('a') == 97
if ht[idx]:
break
else:
ht[idx] = True
else:
repeated = 'no'
print(repeated)