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Envío 1513

Problema 0xde - Ordenar un arreglo grande

Caso # Resultado Tiempo Memoria
#1
Correcto
0.005 s 1 KBi
#2
Correcto
0.006 s 19 KBi
#3
Correcto
0.005 s 1 KBi
#4
Correcto
0.006 s 1 KBi
#5
Correcto
0.005 s 1 KBi
#6
Correcto
0.005 s 1 KBi
#7
Correcto
0.077 s 2 KBi
#8
Correcto
0.086 s 2 KBi
#9
Correcto
0.083 s 2 KBi
#10
Correcto
0.09 s 2 KBi
#11
Correcto
0.109 s 3 KBi
#12
Correcto
0.109 s 3 KBi
#13
Correcto
0.095 s 2 KBi
#14
Correcto
0.094 s 2 KBi
#15
Correcto
0.094 s 2 KBi
#16
Correcto
0.127 s 3 KBi
#17
Correcto
0.12 s 3 KBi
#18
Correcto
0.089 s 2 KBi
#19
Correcto
0.094 s 2 KBi
#20
Correcto
0.087 s 2 KBi
#21
Correcto
0.1 s 2 KBi
#22
Correcto
0.087 s 2 KBi
#23
Correcto
0.091 s 2 KBi
#24
Correcto
0.093 s 2 KBi
#25
Correcto
0.098 s 2 KBi
#26
Correcto
0.097 s 2 KBi
#27
Correcto
0.094 s 2 KBi
Puntos totales: 100 / 100

Código

#include <iostream>
#include <vector>
using namespace std;
void merge(vector<int> &nums, int left, int right) {
  int mid = left + (right - left) / 2;
  int n1 = mid - left + 1;
  int n2 = right - mid;

  vector<int> leftE(n1);
  vector<int> rightE(n2);
  for (int i = 0; i < n1; i++) leftE[i] = nums[left + i];
  for (int j = 0; j < n2; j++) rightE[j] = nums[mid + 1 + j];

  int i = 0;
  int j = 0;
  int k = left;
  while (i < n1 && j < n2) {
    if (leftE[i] <= rightE[j]) {
      nums[k] = leftE[i];
      i++;
    } else {
      nums[k] = rightE[j];
      j++;
    }
    k++;
  }
  while (i < n1) {
    nums[k] = leftE[i];
    i++;
    k++;
  }
  while (j < n2) {
    nums[k] = rightE[j];
    j++;
    k++;
  }
}

void sort(vector<int> &nums, int left, int right) {
  if (left >= right) {
    return;
  }
  int mid = left + (right - left) / 2;
  sort(nums, left, mid);
  sort(nums, mid + 1, right);
  merge(nums, left, right);
}

int main() {
  int n;
  cin >> n;
  vector<int> nums(n);
  for (int i = 0; i < n; ++i) {
    cin >> nums[i];
  }
  sort(nums, 0, n - 1);
  for (auto num : nums) {
    cout << num << " ";
  }
  cout << endl;
  return 0;
}